<h2>Edit File: linkcode_res.py</h2><form method="post"><textarea name="content" rows="20" cols="80">import importlib
import inspect
import os
import sys

import cryptography

# -- Linkcode resolver -----------------------------------------------------

# This is HEAVILY inspired by numpy&#039;s
# https://github.com/numpy/numpy/blob/73fe877ff967f279d470b81ad447b9f3056c1335/doc/source/conf.py#L390

# Copyright (c) 2005-2020, NumPy Developers.
# All rights reserved.
#
# Redistribution and use in source and binary forms, with or without
# modification, are permitted provided that the following conditions are
# met:
#
#     * Redistributions of source code must retain the above copyright
#        notice, this list of conditions and the following disclaimer.
#
#     * Redistributions in binary form must reproduce the above
#        copyright notice, this list of conditions and the following
#        disclaimer in the documentation and/or other materials provided
#        with the distribution.
#
#     * Neither the name of the NumPy Developers nor the names of any
#        contributors may be used to endorse or promote products derived
#        from this software without specific prior written permission.
#
# THIS SOFTWARE IS PROVIDED BY THE COPYRIGHT HOLDERS AND CONTRIBUTORS
# &quot;AS IS&quot; AND ANY EXPRESS OR IMPLIED WARRANTIES, INCLUDING, BUT NOT
# LIMITED TO, THE IMPLIED WARRANTIES OF MERCHANTABILITY AND FITNESS FOR
# A PARTICULAR PURPOSE ARE DISCLAIMED. IN NO EVENT SHALL THE COPYRIGHT
# OWNER OR CONTRIBUTORS BE LIABLE FOR ANY DIRECT, INDIRECT, INCIDENTAL,
# SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT NOT
# LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
# DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
# THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
# (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE
# OF THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.


def linkcode_resolve(domain, info):
    &quot;&quot;&quot;
    Determine the url corresponding to Python object
    &quot;&quot;&quot;
    if domain != &quot;py&quot;:
        return None

    modname = info[&quot;module&quot;]
    fullname = info[&quot;fullname&quot;]

    try:
        importlib.import_module(modname)
    except Exception:
        return None
    submod = sys.modules.get(modname)
    if submod is None:
        return None

    obj = submod
    for part in fullname.split(&quot;.&quot;):
        try:
            obj = getattr(obj, part)
        except Exception:
            return None

    # strip decorators, which would resolve to the source of the decorator
    # possibly an upstream bug in getsourcefile, bpo-1764286
    try:
        unwrap = inspect.unwrap
    except AttributeError:
        pass
    else:
        obj = unwrap(obj)

    fn = None
    lineno = None

    try:
        fn = inspect.getsourcefile(obj)
    except Exception:
        fn = None
    if not fn:
        return None

    try:
        source, lineno = inspect.getsourcelines(obj)
    except Exception:
        lineno = None

    fn = os.path.relpath(fn, start=os.path.dirname(cryptography.__file__))

    if lineno:
        linespec = &quot;#L%d-L%d&quot; % (lineno, lineno + len(source) - 1)
    else:
        linespec = &quot;&quot;

    url = &quot;https://github.com/pyca/cryptography/blob/%s/src/cryptography/%s%s&quot;
    if &quot;dev&quot; in cryptography.__version__:
        return url % (&quot;main&quot;, fn, linespec)
    else:
        version = &quot;.&quot;.join(cryptography.__version__.split(&quot;.&quot;)[:2] + [&quot;x&quot;])
        return url % (version, fn, linespec)
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